010 Editor v8.0.1(32

010 Editor 的逆向分析整体算下来还是比较简单的,将程序拖入OD,通过字符串搜索定位到核心代码,经过分析,主要是如下图所示的两个关键函数,返回正确的值,才算是注册成功。

00409C9B 这个函数返回DB 才是正确的,看下面的关键跳转,这个很好判断。

进入00409C9B 后发现该函数也调用了0040A826的函数,而且这个函数必须返回2D,00409C9B才能返回DB。

所以主要分析0040A826函数让其返回2D就可以了。

进入0040A826函数以后如下图所示

这里有两个关键的函数需要详细的分析:

00407644处函数:

004083C8处函数:

 

分析到这里,我们就可以根据以上分析出来的算法,定位k[3]、k[0]、k[6]、k[1]、k[7]、k[2]、k[5]的值(k[10]就是密码数组)

k[3] = 9C 或 FC 或 AC(010Editor 是有3种注册码的 这里我们只分析k[3] = 9C的情况 这种情况其实密钥只有8位)

AL = (k[0] ^ k[6] ^ 0x18 + 0x3D) ^ A7

ESI = (0X100 * (k1 ^ k7 & 0xFF) + k2 ^ k5 & 0XFF) & 0XFFFF

EAX = (((ESI ^ 0x7892) + 0x4d30) ^ 0x3421) & 0xffff

下面是用c++写的小程序得到上面的值

 1 #include <stdio.h>
 2 #include <time.h>
 3 #include <windows.h>
 4 
 5 int main()
 6 {
 7     srand(time(NULL));
 8     byte K[10] = { 0x00, 0x11, 0x22, 0x9C, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99 };
 9 
10     while (true)
11     {
12         byte k0 = rand() % 0xFF;
13         byte k6 = rand() % 0xFF;
14         byte al = (k0 ^ k6 ^ 0X18 + 0X3D) ^ 0XA7;
15         if (al >= 0)
16         {
17             K[0] = k0;
18             K[6] = k6;
19             break;
20         }
21     }
22     // ESI = ((k[1] ^ k[7] & 0xFF) * 0x100 + k[2] ^ k[5] & 0xFF) & 0xFFFF
23     // EAX = ((EAX ^ 0x7892 + 0x4D30) ^ 0x3421) & 0xFFFF / 0xB
24     // 判断余数,如果余数不为零,返回零,如果余数为零,返回商
25     while (true)
26     {
27         byte k1 = rand() % 0xFF;
28         byte k7 = rand() % 0xFF;
29         byte k2 = rand() % 0xFF;
30         byte k5 = rand() % 0xFF;
31 
32         DWORD ESI = (0X100 * (k1 ^ k7 & 0xFF) + k2 ^ k5 & 0XFF) & 0XFFFF;
33         DWORD EAX = (((ESI ^ 0x7892) + 0x4d30) ^ 0x3421) & 0xffff;
34         if (EAX % 0XB == 0 && EAX/0XB <= 0x3E8)
35         {
36             K[1] = k1;
37             K[7] = k7;
38             K[2] = k2;
39             K[5] = k5;
40             break;
41         }
42     }
43 
44     printf("%02X%02X-%02X%02X-%02X%02X-%02X%02X-%02X%02X\n", K[0], K[1], K[2], K[3], K[4], K[5], K[6], K[7], K[8], K[9]);
45     getchar();
46     return 0;
47 }

 

 

上面程序算出来的值输入后,程序可以断在下面代码处,我们继续分析

这里有个关键函数 00402E50,这个函数传入用户名字符串,返回一个类似哈希值的数据,然后跟密钥产生关系。

我们的做法是直接将程序拖入到IDA,找到00402E50函数,直接F5反编译 ,然后把代码抠出来直接用。

该函数里面有个数组,在OD里面找到这个地址,直接把数组抠出来也可以直接用的。

下面就是完整的注册机代码。

#include <stdio.h>
#include <time.h>
#include <windows.h>

DWORD g_EcodeArray[] = 
{
    0x39cb44b8, 0x23754f67, 0x5f017211, 0x3ebb24da, 0x351707c6, 0x63f9774b, 0x17827288, 0x0fe74821, 0x5b5f670f, 0x48315ae8, 0x785b7769, 0x2b7a1547, 0x38d11292, 0x42a11b32, 0x35332244, 0x77437b60,
    0x1eab3b10, 0x53810000, 0x1d0212ae, 0x6f0377a8, 0x43c03092, 0x2d3c0a8e, 0x62950cbf, 0x30f06ffa, 0x34f710e0, 0x28f417fb, 0x350d2f95, 0x5a361d5a, 0x15cc060b, 0x0afd13cc, 0x28603bcf, 0x3371066b,
    0x30cd14e4, 0x175d3a67, 0x6dd66a13, 0x2d3409f9, 0x581e7b82, 0x76526b99, 0x5c8d5188, 0x2c857971, 0x15f51fc0, 0x68cc0d11, 0x49f55e5c, 0x275e4364, 0x2d1e0dbc, 0x4cee7ce3, 0x32555840, 0x112e2e08,
    0x6978065a, 0x72921406, 0x314578e7, 0x175621b7, 0x40771dbf, 0x3fc238d6, 0x4a31128a, 0x2dad036e, 0x41a069d6, 0x25400192, 0x00dd4667, 0x6afc1f4f, 0x571040ce, 0x62fe66df, 0x41db4b3e, 0x3582231f,
    0x55f6079a, 0x1ca70644, 0x1b1643d2, 0x3f7228c9, 0x5f141070, 0x3e1474ab, 0x444b256e, 0x537050d9, 0x0f42094b, 0x2fd820e6, 0x778b2e5e, 0x71176d02, 0x7fea7a69, 0x5bb54628, 0x19ba6c71, 0x39763a99,
    0x178d54cd, 0x01246e88, 0x3313537e, 0x2b8e2d17, 0x2a3d10be, 0x59d10582, 0x37a163db, 0x30d6489a, 0x6a215c46, 0x0e1c7a76, 0x1fc760e7, 0x79b80c65, 0x27f459b4, 0x799a7326, 0x50ba1782, 0x2a116d5c,
    0x63866e1b, 0x3f920e3c, 0x55023490, 0x55b56089, 0x2c391fd1, 0x2f8035c2, 0x64fd2b7a, 0x4ce8759a, 0x518504f0, 0x799501a8, 0x3f5b2cad, 0x38e60160, 0x637641d8, 0x33352a42, 0x51a22c19, 0x085c5851,
    0x032917ab, 0x2b770ac7, 0x30ac77b3, 0x2bec1907, 0x035202d0, 0x0fa933d3, 0x61255df3, 0x22ad06bf, 0x58b86971, 0x5fca0de5, 0x700d6456, 0x56a973db, 0x5ab759fd, 0x330e0be2, 0x5b3c0ddd, 0x495d3c60,
    0x53bd59a6, 0x4c5e6d91, 0x49d9318d, 0x103d5079, 0x61ce42e3, 0x7ed5121d, 0x14e160ed, 0x212d4ef2, 0x270133f0, 0x62435a96, 0x1fa75e8b, 0x6f092fbe, 0x4a000d49, 0x57ae1c70, 0x004e2477, 0x561e7e72,
    0x468c0033, 0x5dcc2402, 0x78507ac6, 0x58af24c7, 0x0df62d34, 0x358a4708, 0x3cfb1e11, 0x2b71451c, 0x77a75295, 0x56890721, 0x0fef75f3, 0x120f24f1, 0x01990ae7, 0x339c4452, 0x27a15b8e, 0x0ba7276d,
    0x60dc1b7b, 0x4f4b7f82, 0x67db7007, 0x4f4a57d9, 0x621252e8, 0x20532cfc, 0x6a390306, 0x18800423, 0x19f3778a, 0x462316f0, 0x56ae0937, 0x43c2675c, 0x65ca45fd, 0x0d604ff2, 0x0bfd22cb, 0x3afe643b,
    0x3bf67fa6, 0x44623579, 0x184031f8, 0x32174f97, 0x4c6a092a, 0x5fb50261, 0x01650174, 0x33634af1, 0x712d18f4, 0x6e997169, 0x5dab7afe, 0x7c2b2ee8, 0x6edb75b4, 0x5f836fb6, 0x3c2a6dd6, 0x292d05c2,
    0x052244db, 0x149a5f4f, 0x5d486540, 0x331d15ea, 0x4f456920, 0x483a699f, 0x3b450f05, 0x3b207c6c, 0x749d70fe, 0x417461f6, 0x62b031f1, 0x2750577b, 0x29131533, 0x588c3808, 0x1aef3456, 0x0f3c00ec,
    0x7da74742, 0x4b797a6c, 0x5ebb3287, 0x786558b8, 0x00ed4ff2, 0x6269691e, 0x24a2255f, 0x62c11f7e, 0x2f8a7dcd, 0x643b17fe, 0x778318b8, 0x253b60fe, 0x34bb63a3, 0x5b03214f, 0x5f1571f4, 0x1a316e9f,
    0x7acf2704, 0x28896838, 0x18614677, 0x1bf569eb, 0x0ba85ec9, 0x6aca6b46, 0x1e43422a, 0x514d5f0e, 0x413e018c, 0x307626e9, 0x01ed1dfa, 0x49f46f5a, 0x461b642b, 0x7d7007f2, 0x13652657, 0x6b160bc5,
    0x65e04849, 0x1f526e1c, 0x5a0251b6, 0x2bd73f69, 0x2dbf7acd, 0x51e63e80, 0x5cf2670f, 0x21cd0a03, 0x5cff0261, 0x33ae061e, 0x3bb6345f, 0x5d814a75, 0x257b5df4, 0x0a5c2c5b, 0x16a45527, 0x16f23945 };


int __cdecl EncodeUsername(const char *pszUserName, int a2, char a3, short a4)
{
    const char *v4; // edx@1
    signed int v5; // esi@1
    signed int v6; // edi@1
    unsigned __int8 v7; // bl@2
    int v8; // eax@3
    int v9; // ecx@3
    int v10; // ecx@4
    int result; // eax@4
    int v12; // ecx@5
    unsigned __int8 v13; // [sp+8h] [bp-10h]@2
    unsigned __int8 v14; // [sp+Ch] [bp-Ch]@2
    unsigned __int8 v15; // [sp+10h] [bp-8h]@2
    int v16; // [sp+14h] [bp-4h]@1

    v4 = pszUserName;
    v16 = 0;
    v5 = strlen(pszUserName);
    v6 = 0;
    if (v5 <= 0)
    {
        result = 0;
    }
    else
    {
        v13 = 0;
        v14 = 0;
        v7 = 15 * a4;
        v15 = 17 * a3;
        do
        {
            v8 = toupper(v4[v6]);
            v9 = v16 + g_EcodeArray[v8];
            if (a2)
            {
                v10 = g_EcodeArray[v7]
                    + g_EcodeArray[v15]
                    + g_EcodeArray[(unsigned __int8)(v8 + 47)] * (g_EcodeArray[(unsigned __int8)(v8 + 13)] ^ v9);
                result = g_EcodeArray[v14] + v10;
                v16 = g_EcodeArray[v14] + v10;
            }
            else
            {
                v12 = g_EcodeArray[v7]
                    + g_EcodeArray[v15]
                    + g_EcodeArray[(unsigned __int8)(v8 + 23)] * (g_EcodeArray[(unsigned __int8)(v8 + 63)] ^ v9);
                result = g_EcodeArray[v13] + v12;
                v16 = g_EcodeArray[v13] + v12;
            }
            v14 += 19;
            ++v6;
            v15 += 9;
            v7 += 13;
            v13 += 7;
            v4 = pszUserName;
        } while (v6 < v5);
    }
    return result;
}

int main()
{
    srand(time(NULL));
    byte K[10] = { 0x00, 0x11, 0x22, 0x9C, 0x44, 0x55, 0x66, 0x77, 0x88, 0x99 };
    int dwRet = rand() % 0x3E8;
    // 用户名 加密
    char szName[100] = {0};
    printf("请输入用户名:");
    scanf_s("%s", szName, 100);
    DWORD dwKey = EncodeUsername(szName, 1, 0, dwRet);
    // cmp K[4], retValue & 0xFF
    // cmp K[5], retValue >> 8 & 0xFF
    // cmp K[6], retValue >> 16 & 0xFF
    // cmp K[7], retValue >> 24 & 0xFF
    K[4] = dwKey & 0xFF;
    K[5] = dwKey >> 8 & 0xFF;
    K[6] = dwKey >> 16 & 0xFF;
    K[7] = dwKey >> 24 & 0xFF;

    while (true)
    {
        byte k0 = rand() % 0xFF;
        byte k6 = K[6];
        byte al = (k0 ^ k6 ^ 0X18 + 0X3D) ^ 0XA7;
        if (al >= 9)
        {
            K[0] = k0;
            K[6] = k6;
            break;
        }
    }
    // ESI = ((k[1] ^ k[7] & 0xFF) * 0x100 + k[2] ^ k[5] & 0xFF) & 0xFFFF
    // EAX = ((EAX ^ 0x7892 + 0x4D30) ^ 0x3421) & 0xFFFF / 0xB
    // 判断余数,如果余数不为零,返回零,如果余数为零,返回商
    while (true)
    {
        byte k1 = rand() % 0xFF;
        byte k7 = K[7];
        byte k2 = rand() % 0xFF;
        byte k5 = K[5];

        DWORD ESI = (0X100 * (k1 ^ k7 & 0xFF) + k2 ^ k5 & 0XFF) & 0XFFFF;
        DWORD EAX = (((ESI ^ 0x7892) + 0x4d30) ^ 0x3421) & 0xffff;
        if (EAX % 0XB == 0 && EAX/0XB == dwRet)
        {
            K[1] = k1;
            K[7] = k7;
            K[2] = k2;
            K[5] = k5;
            break;
        }
    }

    printf("%02X%02X-%02X%02X-%02X%02X-%02X%02X-%02X%02X\n", K[0], K[1], K[2], K[3], K[4], K[5], K[6], K[7], K[8], K[9]);
    getchar();
    return 0;
}

文章写的比较粗糙,主要是把核心算法和代码写出来了,剩下的就比较简单了。大家有什么问题可以留言,互相交流。

 

010 Editor v8.0.1(32

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